# comparing data sets

Final exam review question #10

I got a test statistic of 1.88329

For which .9699 is the P-value

I don't really know how to evaluate this though... if we're shooting for 95% confidence (which is implicit in the question because its not stated), because the p-value is so large I think I need to subtract it from 1, which gives .0301, which exceeds .025 so we would fail to reject the null?

## Comments

I agree with your test statistic and $p$-value. Given that we're testing for whether $p_D-p_R<0$, yet we've got data satisfying $\hat{p}_D - \hat{p}_R>0$, it's pretty clear that we'll fail to reject the null. I think the problem would be better (more interesting) if I had asked you to test $p_D>p_R$, as suggested by the data.

Super. Please no the way you asked it was just fine!

Well, I think either is fair game for the final so either is worth thinking about.